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Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2+14x+20.

User Andomar
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Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2+14x+20.

we have that

the quadratic formula is equal to


x=\frac{-b\pm\sqrt[\square]{b^2-4ac}_{}}{2a}

where

a=1

b=14

c=20

substitute the given values in the formula


\begin{gathered} x=\frac{-14\pm\sqrt[\square]{14^2-4(1)(20)}_{}}{2(1)} \\ \\ x=\frac{-14\pm\sqrt[\square]{116}_{}}{2} \\ \\ x1=\frac{-14+\sqrt[\square]{116}_{}}{2} \\ \\ x2=\frac{-14-\sqrt[\square]{116}_{}}{2} \end{gathered}

x1 and x2 are the zeros of the quadratic equation

The solutions are real numbers

User Ali Hamad
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