Question

Use a table and graph to show when her investment will be worth 10,000$

Answer 1

I think the interest is compounded yearly, if so

First, convert R as a percent to r as a decimal

r = R/100

r = 6.25/100

r = 0.0625 per year

A = 10000

P = 5000

`A=P(1+(r)/(n))^(nt)`
`\begin{gathered} 10000=5000(1+6.25)^t \\ (10000)/(5000)=(1+0.0625)^t \\ 2=(1.0625)^t \\ \ln 2=\ln (1.0625)^t \\ t=11.5 \end{gathered}`

Use logarithms or a scientific calculator

t = 11.5

In 11.5 years $5000 investment be worth of $10000

>>>>>>>>>>>>>

In case the interest is simple interest

Interest = Amount - Principal = $10000-$5000 = $5000

Time = 100*Interest / (Principal*Rate

= 100*5000 / (5000*6.25)

t = 16 years

In 16 years $5000 investment be worth of $10000