Consider that a linear equation in slope intercept form is given by:
y = mx + b
where m is the slope of the line and b is the y intercept.
use the following formula to calculate the slope m:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
where (x1,y1) and (x2,y2) are two pair of values of the table.
For (x1,y1) = (1,10) and (x2,y2) = (2,20) you have:
![m=(20-10)/(2-1)=10](https://img.qammunity.org/2023/formulas/mathematics/college/aoc1di7z5kz61cnj0jasvdukzhgofnz7o9.png)
Next, use the same formula for m but replacing only the values of (x1,y1), just as follow:
![m=(y-10)/(x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/g0bnmrvdbjqfw1a0pppb9nwrfnhno73q38.png)
and solve for y:
![\begin{gathered} (x-1)m=y-10 \\ (x-1)(10)+10=y \\ 10x-10+10=y \\ y=10x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v3t8r0i0xv6ty32payaiq4m5yt00yp0cz4.png)
Hence, the slope is m = 10 and the y-intercept is b = 0
Then, the linear equation is y = 10x