Question

And you're fine that on his way to work he waits time for the bus is roughly uniformly distributed between 8 minutes and 17 minutes 1 day he time his weight and writes down a number of minutes ignoring the 2nd run a solution to 3 decimal places

Answer 1

We have the waiting times uniformly distributed between 8 and 17 minutes. As he ignore the seconds, we have a discrete distribution with values 8 to 16.

We have to find what is the probaility that the waiting time is 10 minutes.

We can find this probability knowing that 10 is one class out of 17-8=9 classes with equal probability.

So the probability is:

`P(X=10)=(1)/(9)\approx0.111`

We now have to calculate the probability that the waiting time is between equal or higher 11 and less than 13. This include classes 11 and 12 (and not 13), so we include 2 classes out of 9. Then, the probability is:

`P(11\le X\le13)=(2)/(9)\approx0.222`

Answer:

P(X=10) = 0.111

P(11<=X<13) = 0.222