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Please help me solve this problem, it's a part of my homework and I'm just a bit stuck. thank you!

Please help me solve this problem, it's a part of my homework and I'm just a bit stuck-example-1
User BojanT
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1 Answer

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Given triangle is

Using the triangle sum property, we get


\angle A+\angle B+\angle C=180^o
\text{ Substitute }\angle B=85^o\text{ and }\angle C=76^o,\text{ we get}
\angle A+85^o+76^o=180^o


\angle A=180^o-161^o
\angle A=19^o

Given a=1200 yards.

We need to find b and c.

Consider the sine law.


(\sin A)/(a)=(\sin B)/(b)=(\sin C)/(c)


\text{ Substitute }\angle A=19^o,\angle B=85^o\text{,}\angle C=76^o,\text{ and a=1200, we get}


(\sin 19^o)/(1200)=(\sin 85^o)/(b)=(\sin 76^o)/(c)


0.00027=(\sin85^o)/(b)=(\sin76^o)/(c)

Consider the following equation to find the value of b.


0.00027=(\sin85^o)/(b)


b=(\sin 85^o)/(0.00027)
b=3689.6\text{ yards.}

Consider the following equation to find the value of c.


0.00027=(\sin76^o)/(c)


c=(\sin 76^o)/(0.00027)
c=3593.7\text{ yards.}

Hence the distances of the oil platform from each end of the beach are 3689.6 yards and 3592.7 yards.

Please help me solve this problem, it's a part of my homework and I'm just a bit stuck-example-1
User Spacemigas
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