From the question,
We are given
![\sin \theta=-(5)/(13)](https://img.qammunity.org/2023/formulas/mathematics/college/6hvt4zj2fh2ev86glg6zks83pg4bi32n8t.png)
And we are given that θ is in quadrant IV
We are to find
![\tan ((\theta)/(2))](https://img.qammunity.org/2023/formulas/mathematics/college/bkvzocbuf14cimeu7km6ftjd06sehvy1gs.png)
Since Sinθ is in quadrant IV then we have the diagram below
By applying Pythagoreans theorem
![(\text{hyp)}^2=(\text{opp)}^2+(\text{adj)}^2](https://img.qammunity.org/2023/formulas/mathematics/college/e47dn8hqumay2nb4ui02qr4gh06q6noefs.png)
Then we have
![13^2=5^2+x^2](https://img.qammunity.org/2023/formulas/mathematics/college/40mcnoszjg29u5jlmyyxprnjn4lgs8eiou.png)
Solving for x, we get
![\begin{gathered} x^2=13^2-5^2 \\ x^2=169-25 \\ x=\sqrt[]{144} \\ x=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wo90rmwev4k0vvjjft52ie0416yyld9rs7.png)
Therefore, x = 12
From the question, we are to find tan(θ/2)
This will be done using the formula
![\tan ((\theta)/(2))=(\sin \theta)/(1+\cos \theta)](https://img.qammunity.org/2023/formulas/mathematics/college/hiw7q74rlzqr5hwx9rlaty9lqe3g09ychs.png)
Therefore, by applyingthe trigonometrical ratio
SOH CAH TOA
This gives
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