Assuming that the deer is traveling at a constant velocity, we use the following formula.
![d=vt](https://img.qammunity.org/2023/formulas/physics/high-school/ul87ey70wpm37hhqdwgyqp7gz2pid3bo3k.png)
Where d = 1.6 km and v = 8.4 m/s. The velocity is positive because it's going North.
![\begin{gathered} 1.6\operatorname{km}=8.4((m)/(s))\cdot t \\ t=\frac{1.6\operatorname{km}}{8.4((m)/(s))} \end{gathered}]()
But, we have to transform the distance from kilometers to meters. We know that 1000 meters are 1 kilometer.
![1.6\operatorname{km}\cdot\frac{1000m}{1\operatorname{km}}=1600m]()
Once we transform the unit, we can find the time.
![\begin{gathered} t=(1600m)/(8.4((m)/(s))) \\ t\approx190.48\sec \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/wql1wgd918oa60ih3yqtaz0qld2njpaipb.png)
Therefore, the deer will take 190.48 seconds, approximately.