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Solve using substitution 1.) x+y+2z=-7 / -5z=25 / 3x-3y-6z=32.) 2x+3y-4z=-3 / -x-2y+3z=4 /-x-z=4

User Alkino
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1 Answer

3 votes

Okay, here we have this:

We need to solve the following system:

x+y+2z=-7 (1)

-5z=25 (2)

3x-3y-6z=3 (3)

First we are going to clear z in (2):

-5z=25

z=-5

Now let's replace z=-5 in (1):

x+y+2z=-7

x+y+2(-5)=-7

x+y-10=-7 (4)

3x-3y-6z=3

3x-3y-6(-5)=3

3x-3y+30=3 (5)

Now let's clear x in (4):

x+y-10=-7

x=-y+3

Let's replace x=-y+3 in (5):

3x-3y+30=3

3(-y+3)-3y+30=3

-6y+39=3

Now, let's clear y:

-6y+39=3

y=(3-39)/-6

y=-36/-6

y=6

And finally we are going to replace y=6 in x=-y+3

x=-y+3

x=-6+3

x=-3

Finally we obtain that the solution of the system is x=-3, y=6 and z=-5.

User Steve Bryant
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6.3k points