Answer:
L = 0.34 m/s
Step-by-step explanation:
The frequency of sound in the air column closed at one end is given by

where n = harmonic number, v = velocity of sound, and L = length of the pipe.
Now,
![v=331\sqrt[]{(T)/(273)}](https://img.qammunity.org/2023/formulas/physics/college/mc3j5urvahr3b40ezia3a8bk5n0njh0ozl.png)
First, we calculate the sound velocity at T = 22 celsius.
Putting in T = 22 + 273 k into the above equation gives
![v=331\sqrt[]{(22+273)/(273)}](https://img.qammunity.org/2023/formulas/physics/college/rpr0p7edow51yu28z0bj4bplrdd87ca7a5.png)

With the value of v in hand, we calculate the length of the air column for the second resonant length.
Solving for L in the first equation gives

Piutting in n = 2, v = 344.1 m/s, and f_n = 494 m/s gives


Hence, the length of the air column for the second resonant length is 0.35 m.