Question

Use a table of values with at least 5 values to graph the following function:

Answer 1

The given function :

`y=(1)/(2)^x`

Substitute x = 0

`\begin{gathered} y=(1)/(2)^0 \\ y=1 \end{gathered}`

(x,y) = (0,1)

Substitute x =1

`\begin{gathered} y=(1)/(2)^1 \\ y=(1)/(2) \\ y=0.5 \end{gathered}`

(x,y) = (1, 0.5)

Substitute x =(-2)

`\begin{gathered} y=(1)/(2)^((-2)) \\ y=(1^(-2))/(2^(-2))^{} \\ y=(2^2)/(1^2) \\ y=2^2 \\ y=4 \end{gathered}`

So, (x, y) = ( -2, 4)

Substitute x = (-3)

`\begin{gathered} y=(1)/(2)^(-3) \\ y=(1^(-3))/(2^(-3)) \\ y=(2^3)/(1^3) \\ y=2^3 \\ y=8 \end{gathered}`

So, (x,y) = (-3, 8)

Substitute the value of x = (-1)

`\begin{gathered} y=(1)/(2)^(-1) \\ y=(1^(-1))/(2^(-1)) \\ y=(2)/(1) \\ y=2 \end{gathered}`

So, (x, y) = ( -1, 2)

So, the set of coordinates are :

The graph will be :