Slope Intercept Form:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where
m is slope
b is y-intercept (y-axis cutting point)
Now,
We know parallel lines have equal slope.
Let's work with the line equation given to find its slope:
![\begin{gathered} 5x+2y=10 \\ 2y=-5x+10 \\ y=-(5)/(2)x+5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vsyx3h80588e81lrreitanwpl3sfjpy35k.png)
Slope is -5/2. This will be same for our line.
So, we can write:
![y=-(5)/(2)x+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/fbx3l6tpdokso03qilqr77x8ajugx2rxt8.png)
To find b, we put (-6,7) into x and y respectively and find b:
![\begin{gathered} y=-(5)/(2)x+b \\ 7=-(5)/(2)(-6)+b \\ 7=15+b \\ b=7-15 \\ b=-8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8mhro613p9a8oidfwa9mset8ivfzr5vvb4.png)
So, final equation:
![y=-(5)/(2)x-8](https://img.qammunity.org/2023/formulas/mathematics/high-school/hmy8fgx0tklrbpfzhe7zs5xeckkkr0ogak.png)