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3.Write the equation in slope-intercept form for the line that passes through the given pointand is parallel to the given equation.5x + 2y = 10 and passes through (-6, 7)

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Slope Intercept Form:


y=mx+b

Where

m is slope

b is y-intercept (y-axis cutting point)

Now,

We know parallel lines have equal slope.

Let's work with the line equation given to find its slope:


\begin{gathered} 5x+2y=10 \\ 2y=-5x+10 \\ y=-(5)/(2)x+5 \end{gathered}

Slope is -5/2. This will be same for our line.

So, we can write:


y=-(5)/(2)x+b

To find b, we put (-6,7) into x and y respectively and find b:


\begin{gathered} y=-(5)/(2)x+b \\ 7=-(5)/(2)(-6)+b \\ 7=15+b \\ b=7-15 \\ b=-8 \end{gathered}

So, final equation:


y=-(5)/(2)x-8

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