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3) g(x) = 3x + 1, f(x) = x + 5Find (gof)(x)

1 Answer

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(gof)(x) = g[f(x)]

f(x) = x + 5

To find g[f(x)], we will simply substitute x by f(x) into g(x)

That is;

g[f(x)] = 3[f(x)] + 1 = 3 [x+5] + 1

=3x + 15 + 1

=3x + 16

Hence;

(gof)(x) =3x + 16

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