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Find the variance for n = 170 and p = 0.7 when the conditions for the binomial distribution are met.

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If the conditions for a binomial distribution are met, the variance, given the number of trials (n) and the probability of success(p) is given as:


\text{variance (}\sigma^2)\text{ = np(1-p)}

Given:

n = 170

p = 0.7

Solution

By substituting the given values, the variance is:


\begin{gathered} \sigma^2\text{ = 170 }*\text{ 0.7 }*\text{ (1-0.7)} \\ =\text{ 35.7} \end{gathered}

Answer: 35.7

User Milind Ganjoo
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