Answer:
5/48
Explanation:
One object has faces numbered from 1 to 8.
• The sample space of numbers greater than 3 = {4,5,6,7,8}.
Thus:
![P(\text{ rolling a number greater than 3\rparen}=(5)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/jybu4plcg1pkmosi0ryeukb3jkls9x5dlu.png)
The other object has 6 faces labeled M, N, O, P, Q, and R.
![P(\text{ rolling the letter R\rparen}=(1)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/kw8vz4juglb0xc8w53lcwgcq7cuh4jsbpg.png)
Thus, the probability of rolling a number greater than 3 and the number R:
![\begin{gathered} P(number\text{ greater than }4\text{ and R\rparen}=(5)/(8)*(1)/(6) \\ =(5)/(48) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6ft3kynqet220oxjpv02ayx28p96eojtni.png)
The answer is 5/48.