Question

Please help me asap


ty :)

Answer 1

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The line parallel to y = 5x + 9 is given in the form of y = mx + c. Here,

• m = slope
• c = y-intercept (x = 0)

The new line will have a y-intercept and a slope of line which is given by y = 5x + b. The point on line is (-2, -3).

Placing this point in the upper equation,

`:\implies\rm{ - 3 = 5( - 2) + b}`

`:\implies\rm{ - 3 = - 10 + b}`

`:\implies\rm{ - 3 + 10 = b}`

`:\implies\rm{7 = b}`

Placing b = 7 in equation we get,

`:\implies\rm{y = 5x + b}`

`:\implies\rm{y = 5x + 7}`

Answer 2

y = 5x+7

Explanation:

Parallel lines have the same slope so y = 5x+9 is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

The slope is 5

The new line will have a slope of 5

y = 5x+b

We know a point on the line (-2,-3)

Substitute this point into the equation

-3 = 5(-2)+b

-3 = -10+b

-3+10 = b

7 = b

y = 5x+7