ANSWER:
1.188 mm
Explanation:
The first thing is to calculate the length of Matthew's deposit, knowing that it is 10^2 times longer than Josef's.
![0.012\cdot10^2=1.2\operatorname{mm}]()
To know how many millimeters it is longer we must subtract both lengths, like this:
![1.2\operatorname{mm}-0.012\operatorname{mm}=1.188\operatorname{mm}]()
In other words, Matthew's deposit is 1.188 mm (one point one hundred and eighty-eight millimeters) longer than Josef's deposit.