Matthew found a deposit with a diameter that is 10^2 times as long as Josef’s 0.012 millimeter. How many millimeters long is the diameter of Matthew’s deposit? Write your answer…

Question

asked Sep 14, 2023 219k views

1 Answer

Harsh Panchal · Answer 1 · 2023-09-20T06:14:12+0000

ANSWER:

1.188 mm

Explanation:

The first thing is to calculate the length of Matthew's deposit, knowing that it is 10^2 times longer than Josef's.

$0.012\cdot10^2=1.2\operatorname{mm}$

To know how many millimeters it is longer we must subtract both lengths, like this:

$1.2\operatorname{mm}-0.012\operatorname{mm}=1.188\operatorname{mm}$

In other words, Matthew's deposit is 1.188 mm (one point one hundred and eighty-eight millimeters) longer than Josef's deposit.