ANSWER and EXPLANATION
To find the person with the larger paper, we have to find the area of both pieces of paper.
Jada's paper is a rectangular-shaped paper that measures 5 inches by 4 inches.
To find the area of the paper, we have to find the product of its side lengths.
The area of Jada's paper is:
![\begin{gathered} A=5\cdot4 \\ A=20in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wljkhq7pmwpsvb4xw4z342tj7ovoexmioo.png)
Han's paper is shaped like the sector of a circle. The area of the sector of a circle is:
![A=(\theta)/(360)\cdot\pi r^2](https://img.qammunity.org/2023/formulas/mathematics/college/bd5ospf5bpk9aqb0u6werssz2fdqq8nf3q.png)
where θ = angle of the sector
r = radius
We have to find the measure of the angle of the sector by applying the formula for the length of an arc:
![\begin{gathered} L=(\theta)/(360)\cdot2\pi r \\ \Rightarrow2\pi=(\theta)/(360)\cdot2\pi\cdot5 \\ \Rightarrow\theta=(2\pi\cdot360)/(2\pi\cdot5) \\ \theta=72\degree \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3p47eprs8buvnyfwg17kkt6dymrg8kznh8.png)
Hence, the area of Han's paper is:
![\begin{gathered} A=(72)/(360)\cdot\pi\cdot5^2 \\ A=15.7in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mer0l2obc3htoufk61dq64uls3k85nc54j.png)
As we can see, Jada's rectangular piece of paper has an area that is greater than Han's piece of paper shaped like a sector. The area of Jada's piece of paper is 20 in² and the area of Han's piece of paper is 15.7 in²