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45 votes
45 votes
E=4i+3j A=5i finfd E.A=EAcos

User Phonixor
by
2.7k points

1 Answer

13 votes
13 votes

Answer:

theta = 36.87

Explanation:

E.A= (4i+3j).5i= 20

|E| |A| =


| e| |a| = \sqrt{4 ^(2) + {3}^(2) } * 5 = 25


\cos(theta) = (e.a)/( |e ||a | ) = (20)/(25) = (4)/(5) \\ theta = \cos ^( - 1) ( {.8} ) = 36.87

User Balraj
by
2.5k points
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