Question

If you have a 3 L of a 0.6 M solution of AgNO3, then what mass of AgNO3, is contained in this solution?

Answer 1

The mass of AgNO3 contained in the solution is 305.766 grams

Step-by-step explanation

Given that;

The volume of AgNO3 solution is 3L

The concentration of the solution is 0.6M

Follow the steps below to find the mass of AgNO3

Step 1; Find the number of moles of AgNO3 using the below formula

`\text{ molarity = }\frac{\text{ moles}}{\text{ volume}}`

Substitute the given data into the formula above

`\begin{gathered} \text{ 0.6 = }\frac{\text{ mole}}{3} \\ \text{ cross multiply} \\ \text{ mole = 0.6}*\text{ 3} \\ \text{ mole = 1.8 mol} \end{gathered}`

Step 2; Find the mass of AgNO3 using the formula below

`\text{ mole }=\text{ }\frac{\text{ mass}}{\text{ molar mass}}`

Recall, that the molar mass of AgNO3 is 169.87 g/mol

`\begin{gathered} \text{ 1.8 }=\text{ }\frac{\text{ mass}}{\text{ 169.87}} \\ \text{ cross multiply} \\ \text{ mass = 1.8 }*\text{ 169.87} \\ \text{ mass = 305.766 grams} \end{gathered}`

Therefore, the mass of AgNO3 contained in the solution is 305.766 grams