Question

Fill in the missing values to make the equation true.

Answer 1

`\log _87-log_83=log_8\text{ }(7)/(3)`

Explanation:

Below is the given logarithm function

`\log _87-log_83`

To simplify this expression, we need to apply the rules of the logarithm

Assuming we have Log A - log B with a common base

`\begin{gathered} \text{According to the law of logarithm} \\ \log _xA-log_xB=\log _x(A)/(B)_{} \end{gathered}`

Hence,

`\text{log}_87-log_83=log_8(7)/(3)`