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y 12 11 10 9 18 5 NCS A 1 X -12-11-10-9-8-7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 11 12 -1 3 ó do & och ich -10 -11 -12

y 12 11 10 9 18 5 NCS A 1 X -12-11-10-9-8-7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 11 12 -1 3 ó do-example-1
User Aroc
by
6.3k points

1 Answer

7 votes

To find out the equation of the line we need two points

so

we take

(1,-3) and (2,-9)

step 1

Find the slope

m=(-9+3)/(2-1)

m=-6/1

m=-6

step 2

Find the equation in slope intercept form

y=mx+b

we have

m=-6

point (1,-3)

substitute

-3=-6(1)+b

solve for b

-3=-6+b

b=6-3

b=3

therefore

y=-6x+3

User Miyoshi
by
6.0k points