Answer:
The common difference, d = 5
![\begin{gathered} T_n=5n+4 \\ T_9=49 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nh652jc4v6fq7fuqdn5xlli0fuphwq5whp.png)
Step-by-step explanation:
The given sequence is:
9, 14, 19
The common difference is the difference between the consecutive terms of the sequence.
The common difference, d = 14 - 9 or d = 19 - 14
Therefore, the common difference, d = 5
The nth term of an Arithmetic sequence is given by the formula:
![T_n=a+(n-1)d](https://img.qammunity.org/2023/formulas/mathematics/college/ujlf0eeq649bapnzc8br3v1ywnl1cgk7ik.png)
where the first term, a = 9
The common difference, d = 5
Substitute a = 9, and d = 5 into the nth term formula above
![\begin{gathered} T_n=9+5(n-1) \\ T_n=9+5n-5 \\ T_n=5n+4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/lc4btpjwravd1vbxxjjffmblmmdgpgwqe2.png)
The 9th term in the sequence is calculated by substituting n = 9 into the nth term gotten above
![\begin{gathered} T_n=5n+4 \\ T_9=5(9)+4 \\ T_9=45+4 \\ T_9=49 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rajgn01b3vojd7iypxkvwbzkoer4tt71d5.png)