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Write the equation of the line; with the given properties, in slope-intercept form. Slope=-5 through (-5, 5) Could you explain I don’t understand please.

User Kuno
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The equation of the line;


y=-5x-20

Problem statement

Write the equation of the line; with the given properties, in slope-intercept form.

Slope (m)= -5 through (-5, 5)

Solution

The slope-intercept form of a line is y = mx + b, where m is the slope and b is the

y-intercept.


\begin{gathered} y=mx+b \\ y=-5x+b \end{gathered}

Since (-5, 5 ) is a point on the line, we can "plug in" -5 for x and 5 for y into our equation to obtain


\begin{gathered} y=-5x+b \\ 5=-5(-5)+b \\ \text{open the bracket} \\ 5=25+b \\ \text{rewrite} \\ 25+b=5 \\ \text{subtract 25 from both sides} \\ 25-25+b=5-25 \\ b=-20 \\ \end{gathered}

We now substitute for b now


y=-5x-20

The equation of the line;


y=-5x-20

User Nakamura
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