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What is the equation of a line that is perpendicular to the line y = -¼x – 1 and passes throughthe point (3, 7)?

User Frandy
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1 Answer

6 votes

Given the equation:

y = -¼x - 1

And it passes through the point (3, 7)

Using the slope intercept form: y = mx + b

where m is the slope.

The slope of a perpendicular line is the inverse

The slope here is: 4 which is the inverse of -¼

Thus, we have:

(x, y) ==>(3, 7)

Substitute x for 3

Substitute y for 7

7 = 4(3) + b

7 = 12 + b

Let's solve for b:

7 - 12 = b

-5 = b

Therefore, the equation is:

y = 4x - 5

User LucaM
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