Question

a force of 10n causes a spring to extend by 2mm find a,the spring constant of the spring in N/w b,the extension of the spring when 25N is applied c,the force applied that caused an extension of 5mm​

Answer 1

a. Use Hooke's law to find the spring constant k :

F = kx ⇒ 10 N = k (2 mm) = k (0.002 m) ⇒ k = 5000 N/m

b. Use Hooke's law again to find the extension x given a force of 25 N :

F = kx ⇒ 25 N = (5000 N/m) x ⇒ x = 0.005 m = 5 mm

c. We end up with the same force as in part (b) :

F = kx ⇒ F = (5000 N/m) (5 mm) = (5000 N/m) (0.005 m) = 25 N