Question

Please help me. nobody has been able to so far

Answer 1

Given:

Height = 15 feet

Let's solve for the following:

• (a) Write an equation that shows how the ball's height above the water, h, is related to elased time, t.

To write the equation that shows the height of ball, we have:

`h(t)=15-16t^2`

• (b). Estimate the time it will take the ball to hit the water.

At the time the ball will hit the water, the height of the ball will be 0 feet.

Thus, to find the time, substitute 0 for h(t) and solve for t.

We have:

`\begin{gathered} h(t)=15-16t^2 \\ \\ 0=15-16t^2 \\ \\ 16t^2=15 \end{gathered}`

Divide both sides by 16:

`\begin{gathered} (16t^2)/(16)=(15)/(16) \\ \\ t^2=0.9375 \end{gathered}`

Take the square root of both sides:

`\begin{gathered} \sqrt[]{t^2}=\sqrt[]{0.9375} \\ \\ t=0.97 \end{gathered}`

Therefore, it will take the ball 0.97 seconds to hit the water.

ANSWER:

• (a). h(t) = 15 - 16t²

• (b). 0.97 seconds