Since we have that BD is the median, it divides the segment or side of the triangle into two equal parts. Then, we have that:
![AD=CD\Rightarrow6x+10=2x+12](https://img.qammunity.org/2023/formulas/mathematics/college/ryha44cdghkwswo63ul4ko75em18w33ysh.png)
Then, we need to solve the equation for x, and to do so, we need to:
1. Subtract 2x, and 10 from both equations:
![6x-2x+10-10=2x-2x+12-10\Rightarrow6x-2x=12-10](https://img.qammunity.org/2023/formulas/mathematics/college/yi5vse2ofcf8xjnc4wx8t4dafi8c1r565p.png)
2. Since we have like terms, then we have:
![6x-2x=12-10\Rightarrow4x=2\Rightarrow(4)/(4)x=(2)/(4)\Rightarrow x=(2)/(4)\Rightarrow x=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/vanq4ing1cf607dh6enm89riahtw9p9ruu.png)
In the previous step, we divide both sides of the equation by 4 and then simplify the resulting fraction.
Hence, the value for x = 1/2. The length of AC is the sum of AD + CD or twice the value of one of them:
![AD+CD=6x+10+2x+12=6\cdot(1)/(2)+10+2\cdot(1)/(2)+12=(6)/(2)+10+(2)/(2)+12](https://img.qammunity.org/2023/formulas/mathematics/college/altlrdwnjt9kj1wac4rd6am1s8ygrlie32.png)
Therefore, the length of AC is
![AC=3+10+1+12\Rightarrow AC=26](https://img.qammunity.org/2023/formulas/mathematics/college/aj3q3ayrbf1oz6fqsmhi7anoccg7fa9vf7.png)
AC = 26 units.