Question:
Simplify the trig expression. sin x tan x +cos x.
Solution:
Let the following trigonometric expression:
![\sin (x)\tan (x)\text{ + cos(x)}](https://img.qammunity.org/2023/formulas/mathematics/college/xzi48mkg5xkpt57go09wn4zj7pen696r93.png)
Rewriting using trigonometric identities:
![=\text{ }cos(x)\text{ +}(\sin(x))/(\cos(x))\sin (x)](https://img.qammunity.org/2023/formulas/mathematics/college/u60dg3vgrsakfj0ede6s254utxejxloxn9.png)
this is equivalent to:
![=\text{ }cos(x)\text{ +}(\sin ^2(x))/(\cos (x))](https://img.qammunity.org/2023/formulas/mathematics/college/na9uaf1coqxlaa9zyrv8vr1dub3x3bdfd4.png)
Converting cos (x) to a fraction, this is equivalent to:
![=\text{ }(\cos (x)\cos (x))/(\cos (x))\text{+}(\sin^2(x))/(\cos(x))](https://img.qammunity.org/2023/formulas/mathematics/college/2lqnp7i29ao5ziyi9onbycoijeubhysjxx.png)
Since the denominators are the same, we can combine the fractions:
![=\text{ }(\cos (x)\cos (x)+sin^2(x))/(\cos (x))](https://img.qammunity.org/2023/formulas/mathematics/college/qmrp6d7ov9u1hgreu72tzgiy24g4m0iczk.png)
this is equivalent to:
![=\text{ }(\cos ^2(x)+sin^2(x))/(\cos (x))](https://img.qammunity.org/2023/formulas/mathematics/college/lww3v4383j91tywl7as1itf5s83xa3ae7b.png)
this is equivalent to:
![=\text{ }(1)/(\cos (x))=\text{ }sec(x)](https://img.qammunity.org/2023/formulas/mathematics/college/yxn9ztx9ajgtgntvxf0mazzpn2k0kqx5f8.png)
then, we can conclude that the correct answer is :
![\sin (x)\tan (x)\text{ + cos(x) = sec(x)}](https://img.qammunity.org/2023/formulas/mathematics/college/5443nb6bm90zx98es0ojl4b7avyut29m01.png)