The first step to answer this question is to convert the given mass (68g LiNO3) to moles using the molar mass of lithium nitrate:
![68gLiNO_3\cdot(1molLiNO_3)/(68.946gLiNO_3)=0.98molLiNO_3](https://img.qammunity.org/2023/formulas/chemistry/college/lpmpgif4vzrl8qupfrg2dn29j484aamv2k.png)
According to the given equation, 4 moles of LiNO3 produce 1 mole of Pb(NO3)4, the next step is to use this ratio to determine how many moles of Pb(NO3)4 are produced:
![0.98molLiNO_3\cdot(1molPb(NO_3)_4)/(4molLiNO_3)=0.245molPb(NO_3)_4](https://img.qammunity.org/2023/formulas/chemistry/college/qbxvcvy2ocfebrgss9nnr0jutiufb56ly7.png)
It means that 0.245 moles of lead (IV) nitrate are produced.