√(28)simplest radical form

Question

`√(28)`simplest radical form

Answer 1

Recall following property of radicals:

`\sqrt[]{a\cdot b}=\sqrt[]{a}\cdot\sqrt[]{b}`

Since 28 can be factorized as:

`2^2\cdot7`

Use the property previoulsy mentioned to rewrite the square root of 28:

`\begin{gathered} \sqrt[]{28}=\sqrt[]{2^2\cdot7} \\ =\sqrt[]{2^2}\cdot\sqrt[]{7} \\ =2\cdot\sqrt[]{7} \end{gathered}`

Therefore, the simplest radical form of the square root of 28, is:

`2\cdot\sqrt[]{7}`