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Find the area of an equilateral triangle with side lengths of 10ft. (round to the nearest tenth)

User Bakasan
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Answer:

The area of the triangle is;


43.3\text{ square ft}

Step-by-step explanation:

Given an equilateral triangle with sides 10ft.

Recall that the area of a triangle can be calculated using the formula;


A=(1)/(2)bh

The height of the triangle would be;


\begin{gathered} h=\sqrt[]{10^2-5^2} \\ h=\sqrt[]{75}^{} \\ h=5\sqrt[]{3} \end{gathered}

and the base length is;


b=10

substituting;


\begin{gathered} A=(1)/(2)bh=(1)/(2)*10*5\sqrt[]{3} \\ A=25\sqrt[]{3} \\ A=43.3\text{ square ft} \end{gathered}

Therefore, the area of the triangle is;


43.3\text{ square ft}

User Tys
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