Question

Two teams working together can finish a job in 8 days. if the first team works alone for two days and the second team works alone for 5 days, 5/8 of the total work still remains. How many days will it take each team to finish the work alone?

Answer 1

x is the days that the first team finishes the work alone (x>8)

y --------------------------second-----------------------------------------(y>8)

In a day:

• The first team finishes 1/x (the work)

• The second team finishes 1/y (the work)

• Two teams working together finish 1/8 (the work)

⇒
`(1)/(x)+ (1)/(y) =(1)/(8)` (1)

If the first team works alone for two days and the second team works alone for 5 days, 5/8 of the total work still remains:

⇒
`(2)/(x)+(5)/(y)=(3)/(8)` (2)

(1),(2) ⇒
`\left \{ {{(1)/(x)+ (1)/(y) =(1)/(8)} \atop {(2)/(x)+(5)/(y)=(3)/(8)}} \right. <=>\left \{ {{x=16} \atop {y=24}} \right.`

It'll take the first team 16 days and the second team 24 days to finish the work alone

ok done. Thank to me :>