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Given the function f(x)=3/4x^2-x, then what is f(x-1) as a simplified polynomial?

User Danomarr
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1 Answer

3 votes

Answer:

f(x-1) = (3/4)x² - (5/2)x + 7/4

Step-by-step explanation:

To find f(x-1), we need to replace x by (x-1) on the equation of f(x), so


\begin{gathered} f(x)=(3)/(4)x^2-x \\ f(x-1)=(3)/(4)(x-1)^2-(x-1) \end{gathered}

Then, we can simplify the polynomial


\begin{gathered} f(x_{}-1)=(3)/(4)(x^2-2x+1)-x+1 \\ f(x-1)=(3)/(4)x^2-(3)/(4)(2x)+(3)/(4)-x+1 \\ f(x-1)=(3)/(4)x^2-(3)/(2)x-x+(3)/(4)+1 \\ f(x-1)=(3)/(4)x^2-(5)/(2)x+(7)/(4) \end{gathered}

Therefore, the simplified polynomial for f(x-1) is

f(x-1) = (3/4)x² - (5/2)x + 7/4

User Rahul Dole
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