Answer:
Solution given:
Construction:
EF parallel to AB and CD is drawn.
let suppose <AEF=a
and
<CEF=b
now
<EAB+<EAB=180°[being co interior angle]
116°+a=180°
a=180°-116°=64°
again
<DCE +<CEF=[being co interior angle]
124°+b=180°
b=180°-124°
b=56°
Now
we know
x=a+b=64°+56°=120°
Value of x is 120°