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Find an nth-degree polynomial function with real coefficients satisfying the given conditin=3;3 and 5 i are zeros;f(1) = -52

User Abril
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1 Answer

4 votes

Given:

3 and 5i are the roots of the equation.

It is given that n=3 .

Let assume the third root be the conjugate of complex root that is -5i

Then the polynomial function :


f(x)=(x-3)(x-5i)(x+5i)
f(x)=(x-3)(x^2+25)
f(x)=x^3+25x-3x^2-75
f(x)=x^3-3x^2+25x-75
\text{The polynomial function be }f(x)=x^3-3x^2+25x-75

Given that f(1)= -52,


f(1)=1-3+25-75
f(1)=-52

User James Geddes
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