Question:
Solution:
Consider the following diagram that represents the given problem:
Now, since P is the midpoint of DE, we get the following equation:
![DE\text{ = DP + PE = DP + DP = 2(DP)}](https://img.qammunity.org/2023/formulas/mathematics/college/vyv0xbbt99a9vklnw55u5l8vpwdvalx9fh.png)
According to the diagram, this is equivalent to:
![14x-10=DE\text{ = 2(DP) = 2(6x+4)}](https://img.qammunity.org/2023/formulas/mathematics/college/p2kz0a9pw9o3fl54teyxqkwduv7hcvab08.png)
this is equivalent to:
![14x-10\text{ = 2(6x+4)}](https://img.qammunity.org/2023/formulas/mathematics/college/1a6gkfcsor6v5tcquazkz50oy01ctgfrwi.png)
Applying the distributive property, this is equivalent to:
![14x-10\text{ = }12x\text{ + 8}](https://img.qammunity.org/2023/formulas/mathematics/college/do5fwisiohuaozctsc8zou0e2f2fpi80p3.png)
putting together similar terms, this is equivalent to:
![14x\text{ - 12x = 8 + 10 }](https://img.qammunity.org/2023/formulas/mathematics/college/2vvduwtlw3b7hza14s8an4c6oa57fb60ps.png)
this is equivalent to:
![2x\text{ = 18}](https://img.qammunity.org/2023/formulas/mathematics/college/nrm85gm6d0pjzdce2docnk7kddju6nndrh.png)
solving for x, we get:
![x\text{ = }(18)/(2)\text{ =9}](https://img.qammunity.org/2023/formulas/mathematics/college/vlzj36izyfmsupgsrvjzobolx8e6noqocw.png)
replacing this into the following equation:
![DP\text{ = 6x+4}](https://img.qammunity.org/2023/formulas/mathematics/college/nfz534lxebomsod6frz7t0gzyflx8wms9s.png)
we get:
![DP\text{ = 6x+4 = 6(9)+4 = 54 + 4 = 58}](https://img.qammunity.org/2023/formulas/mathematics/college/rnt7hiqo82hiwikgp88ne68qp0v4cnlimv.png)
so that, we can conclude that the correct answer is:
![DP\text{ = 58}](https://img.qammunity.org/2023/formulas/mathematics/college/7pu2f6wv17myyq32rxjttxcvkl3nfkde92.png)