Question

What is the volume of the cone when the base is 16yd and the height of 16yd?

Answer 1

Step 1: Given the volume of the cone having base and height

Base = diameter = 16yrd

Diameter = 2 x radius

D= 2r

Height = 16yd

`\begin{gathered} R\text{adius = }(Diameter)/(2)\text{ } \\ R\text{ = }(D)/(2)\text{ = }(16yd)/(2)\text{ = 8yd} \end{gathered}`

Step 2: Find the Volume of a cone having base and height

`\begin{gathered} \text{Volume of a cone = }(1)/(3)\pi^{}r^2h \\ V\text{ = }(1)/(3)\text{ }*\text{ }(22)/(7)\text{ }**(8yd)^2*\text{ 16yd} \\ V\text{ = }(22528)/(21)yd^3 \\ V=1072.76yd^{3\text{ }} \\ V=1072.8yd^3 \end{gathered}`

Hence the Volume of a cone = 1072.8yd³