Question

***I NEED TO FIND THE SLOPE OF THE LINE THOUGH THESE POINTS****

Answer 1

We need to find the slope of a segment that joins the points (5, -2), and (-5, -8)

Therefore we use the formula for the slope:

`\text{slope}=(y_2-y_1)/(x_2-x_1)=(-8-(-2))/(-5-5)=(-6)/(-10)=0.6`

Therefore the value of the slope is 0.6 = 6/10 = 3/5

You may need to enter the answer in a particular format (all three values above are the same, but expressed differently)

Then if we want the expression for the equation of the line, we use this slope, and either one of the points that they give us. for example the point (5, -2)

We write the general form of the equation of a line in slope-intercept form:

`y=mx+b`

and use for "m" 3/5, and require that the point (5, -2) be part of the line:

`\begin{gathered} y=(3)/(5)x+b \\ -2=(3)/(5)(5)+b \\ -2=3+b \\ -2-3=b \\ b=-5 \end{gathered}`

Therefore, the equation of the line (in slope intercept form) is:

`y=(3)/(5)x-5`