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Two buses leave a station at the same time and travel in opposite directions. One bus travels 9 km/h slower than the other. If the two buses are 514 kilometers apart after 2 hours, what is the rate of each bus?

User NVM
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1 Answer

5 votes

\begin{gathered} \text{distance (d)} \\ d1+d2=514 \\ d1=v1\cdot t \\ d2=v2\cdot t \\ v=\text{speed or rate, t=time} \end{gathered}
\begin{gathered} v1\cdot2+v2\cdot2=514 \\ v1\cdot2+(v1-9)\cdot2=514 \\ 2v1+2v1-18=514 \\ 4v1=514+18 \\ 4v1=532 \\ v1=133\text{ km/h} \\ v2=133-9 \\ v2=124\text{ km/h} \end{gathered}

User FeignMan
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