23.3k views
4 votes
I tried to solve this but I immediately got confused.

I tried to solve this but I immediately got confused.-example-1

1 Answer

4 votes

Firstly, let us find the perimeter.

Perimeter P is;


P=AB+BC+AC

The length of AB and AC can be calculated using the formula for distance between two points.


\begin{gathered} AB=\sqrt[]{4^2+2^2} \\ AB=\sqrt[]{16+4} \\ AB=\sqrt[]{20} \\ AB=4.47\operatorname{cm} \end{gathered}
\begin{gathered} AC=\sqrt[]{4^2+4^2} \\ AC=\sqrt[]{16+16} \\ AC=\sqrt[]{32} \\ AC=5.66\operatorname{cm} \end{gathered}
BC=6\operatorname{cm}

substituting we have;


\begin{gathered} P=AB+BC+AC \\ P=4.47\operatorname{cm}+6\operatorname{cm}+5.66\operatorname{cm} \\ P=16.13\operatorname{cm} \end{gathered}

The perimeter is 16.13 cm.

Secondly, The Area A.


A=(1)/(2)bh
undefined

User Fumie
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories