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I tried to solve this but I immediately got confused.

I tried to solve this but I immediately got confused.-example-1

1 Answer

4 votes

Firstly, let us find the perimeter.

Perimeter P is;


P=AB+BC+AC

The length of AB and AC can be calculated using the formula for distance between two points.


\begin{gathered} AB=\sqrt[]{4^2+2^2} \\ AB=\sqrt[]{16+4} \\ AB=\sqrt[]{20} \\ AB=4.47\operatorname{cm} \end{gathered}
\begin{gathered} AC=\sqrt[]{4^2+4^2} \\ AC=\sqrt[]{16+16} \\ AC=\sqrt[]{32} \\ AC=5.66\operatorname{cm} \end{gathered}
BC=6\operatorname{cm}

substituting we have;


\begin{gathered} P=AB+BC+AC \\ P=4.47\operatorname{cm}+6\operatorname{cm}+5.66\operatorname{cm} \\ P=16.13\operatorname{cm} \end{gathered}

The perimeter is 16.13 cm.

Secondly, The Area A.


A=(1)/(2)bh
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