Question

Use the remainder theorem to find the remainder when 3x^4 - 5x^2 - 20x + 8 is divided by x - 1.-414-140

Answer 1

The given equatiion is:

`3x^4-5x^2-20x+8`

To be divided by x-1

set the expression to zero:

`\begin{gathered} x-1=0 \\ x=1 \end{gathered}`

Substitute x=1 into the polynomial:

`3(1)^4-5(1)^2-20(1)+8`

This gives:

`3-5-20+8=-14`

Therefore the remainder is -14.