151k views
2 votes
Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions to the equation? Explain how you know.

Here is a graph of the equation 2y - x = 1.Are the points (0, 1/2) and (-7, -3) solutions-example-1

1 Answer

5 votes

Given the graph of the equation:


2y-x=1

we will check if the points (0, 1/2) and (-7, -3) solutions to the equation

So, we will substitute the points into the equation

The first point (0, 1/2)

Substitute with x = 0, and y = 1/2

so,


LHS=2\cdot(1)/(2)-0=1=R\mathrm{}H\mathrm{}S

So, the point (0, 1/2) is a solution to the equation and as shown in the figure the line passes through the point which is the y-intercept

The second point (-7, -3)

Substitue with x = -7, and y = -3

so,


LHS=2\cdot-3-(-7)=-6+7=1=R.H.S

So, the point (-7, -3) is a solution to the equation.

User Sam Murphy
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories