The formula for compounded interest is as follows:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Where A is the final amount, P is the principal amount (the initial amount), r is the annual interest rate, n is how many times it is compounded per year and t is the time in years.
We already have:
![\begin{gathered} P=2000 \\ r=12\%=0.12 \\ t=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z3vfcwsbx8vj4pj0ghvcljazn3m75x5mci.png)
Also, we know that it is compounded monthly. Since there are 12 month per year, each ear it will be compounded 12 times:
![n=12](https://img.qammunity.org/2023/formulas/mathematics/high-school/l6xrfmvkmidxtlqqijnqsox8k8056o0r6r.png)
Now, to get the final amount, we just need to substitute this values and evaluate:
![\begin{gathered} A=P(1+(r)/(n))^(nt) \\ A=2000(1+(0.12)/(12))^(12\cdot6) \\ A=2000(1+0.01)^(72) \\ A=2000(1.01)^(72) \\ A=2000\cdot2.0470\ldots \\ A=4094.1986\ldots\approx4094.20 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zwqyndrgqki2z38z44s2w24odcahhz7sa9.png)
So, the future value is approximately $4094.20.