As per given by the question,
The average grade of the first professor is 85%, and their standard deviations is 2%.
The average grade of the second professor is 50%, and their standard deviations is 15%.
Now,
The standard deviation for first professor is denoted by

The standard deviation of second professor is,

Now,
from normal distribution formula,
![y=\frac{1}{\sigma\sqrt[]{2\pi}}e^{-((x-\mu)/(2\sigma^2)}](https://img.qammunity.org/2023/formulas/mathematics/college/5wuee4ebpjaviyweojbvb3y6tzzl6xxowg.png)
Then,
![\begin{gathered} y1=\frac{1}{2\sqrt[]{2\pi}}e^{-(0.85)/(8)} \\ =0.1719 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2p3xi1eja9wntpjc8fmrped53o3amsk1ej.png)
Now,
For second professor,
![\begin{gathered} y2=\frac{1}{15\sqrt[]{2\pi}}e^{-((0.50)/(450)}) \\ =0.099 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rmf57kesj2v7vu6hrs37jxo9kolqz7ugxb.png)
Now,
The probability that pass the second professor is,

Hence, the probability that pass the second professor is 0.57.