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Please help:Solve for t.19 = 1/2 gt^2A. t=38/g−−√B. t=76/g−−√C. t=(38/g)^2D. t=g/76−−√

Please help:Solve for t.19 = 1/2 gt^2A. t=38/g−−√B. t=76/g−−√C. t=(38/g)^2D. t=g/76−−√-example-1
User Cessor
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1 Answer

1 vote

Given:


19=(1)/(2)gt^2

We will solve the equation to find (t) as follows:


\begin{gathered} 19=(1)/(2)gt^2\rightarrow*2 \\ 2*19=2*(1)/(2)gt^2 \\ 38=gt^2 \\ t^2=(38)/(g) \\ \\ t=\sqrt{(38)/(g)} \end{gathered}

So, the answer will be the first option.

User Mateus Gondim
by
8.5k points
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