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What is the mass of 5.6 x 1026 molecules of Al2O3?

1 Answer

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Answer:


94,883.72\text{ g}

Step-by-step explanation:

Here, we want to get the mass that contains the given number of molecules

We start by getting the number of moles

Mathematically:


1\text{ mole has 6.02 }*\text{ 10}^(23)\text{ molecules}

The number of moles in the given number of molecules would be:


\frac{5.6\text{ }*\text{ 10}^(26)}{6.02\text{ }*\text{ 10}^(23)}\text{ = 930.23 moles}

Now from here, we get the mass

Mathematically:


mass\text{ = number of moles }*\text{ molar mass}

The molar mass of the compound is 102 g/mol

Thus, we have the mass as:


930.23\text{ }*\text{ 102 = 94,883.72 g}

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