Question

Find the zeros of the function f(x) = (x+3)^2-4=0

Answer 1

`x=-1` and
`x=-5`

Explanation:

`f(x)=(x+3)^2-4`

`0=(x+3)^2-4`

`0=(x^2+6x+9)-4`

`0=x^2+6x+5`

`0=(x+1)(x+5)`

`x=-1` and
`x=-5`

Answer 2

`x=-1,\:x=-5`

Explanation:

Solve the equation:

`f(x)=\left(x+3\right)^2-4=0`

`\left(x+3\right)^2-4=0`

`\mathrm{Add\:}4\mathrm{\:to\:both\:sides}`

`\left(x+3\right)^2-4+4=0+4`

`\left(x+3\right)^2=4`

`x+3=√(4):x=-1`

`x+3=√(2^2)`

`x+3=2`

`x+3-3=2-3`

`x=-1`

`x+3=-√(4):x=-5`

`x+3=-√(4)`

`x+3=-2`

`x+3-3=-2-3`

`x=-5`

Now, look at the points plotted on the graph: