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Find the common difference for a_n=1/7+2nGiven: the first term is 1/9

1 Answer

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Given:

The sequence is:


a_n=(1)/(7+2n)

The first term


a_1=(1)/(9)

Required:

Find the common difference of the sequence.

Step-by-step explanation:

The given sequence is


\begin{gathered} a_(n)=(1)/(7+2n) \\ a_1=(1)/(9) \end{gathered}

Substitute n = 2


\begin{gathered} a_2=(1)/(7+2(2)) \\ a_2=(1)/(7+4) \\ a_2=(1)/(11) \end{gathered}

Substitute n = 3


\begin{gathered} a_3=(1)/(7+2(3)) \\ a_3=(1)/(7+6) \\ a_3=(1)/(13) \end{gathered}

Thue the numbers of the sequence are:


(1)/(9),(1)/(11),(1)/(13),....

The given sequence is in HP.

Write it in AP as:


9,11,13

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