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F(a) = a - 2g(a) = -3a² - 1Find (fºg)(a)

1 Answer

7 votes

Given,


\begin{gathered} f(a)=a-2 \\ g(a)=-3a^2-1 \end{gathered}

Then,


(f\circ g)(a)=f(g(a))
\begin{gathered} (f\circ g)(a)=f(-3a^2-1) \\ (f\circ g)(a)=(-3a^2-1)-2=-3a^2-3 \end{gathered}

User Jason Voegele
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