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Add (2xy2 + 15x – 6) + (3xy2 – y + 5)

User NewbiZ
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1 Answer

6 votes

To add, (2xy²+ 15x – 6) + (3xy² – y + 5)

Step-by-step explanation:

It is given that,

(2xy²+ 15x – 6) + (3xy² – y + 5)

That implies,


\begin{gathered} \left(2xy²+15x-6\right)+(3xy²-y+5)=(2xy^2+3xy^2)+15x-y+(-6+5) \\ =5xy^2+15x-y-1 \end{gathered}

Hence, the answer is 5xy² +15x -y-1.

User DPG
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